Ningbo Lida Pneumatic Complete Sets Co.,Ltd.  
Languages: CHINESE / ENGLISH
Home About Us honor&culture Products New products News center Download Contact us
Air treatment units
Directional control valve
Pneumatic control valve
Air cylinder
Pneumatic accessory
 
Please select product classification
Please fill in product key words
Home >> New center
How to Calculate Pneumatic Cylinder Force

Measure the size of the air cylinder to calculate the total area that the air will be pushing against to create the force. Allpneumatic cylinders are classified by the diameter of the cylinder and the length of the stroke. The most important measurement we need in calculating force is the diameter of the cylinder.

Step 2Find the total area in the pneumatic cylinder if the diameter is 4 inches. To find the area of a round circle for any object, the formula is A= (pi) x (Rsquared). Where A is equal to area, pi is equal to 3.1416 and Rsquared is the radius of the circle squared.

Step 3Calculate the area of the 4-inch diameter circle by first multiplying the radius times itself. This would equal 2 inches as the radius, times itself or 2 X 2 is equal to 4. Next multiply pi (3.1416) times the 4 and the answer is 12.5664 square inches. So the total area of the air cylinder is equal to 12.5664 inches^2, read as inches squared.

Step 4Find the total force from the air cylinder if the air pressure is equal to 100 PSI. Since PSI is equal to pounds per square inch, all we need to do is multiply the total area in square inches of the pneumatic cylinder times the air pressure in PSI. The total force delivered from the 4-inch diameter air cylinder with 100 PSI of air pressure would equal 12.5664 inches^2 times 100 PSI, which is equal to 1,256.4 pounds of force.

Step 5Understand that the 1,256.4 pounds of force would be on the push stroke only and not on the retraction end of the cylinder. The diameter of the push rod must be subtracted from the overall area, as the connection of the push rod interferes with the force measurement.

Step 6Find the area of the push rod for the retraction force measurement if the push rod is 2 inches in diameter. Using the formula from Step 3, the area of the push rod would be A = (3.1416) times 1^2, which is equal to 3.1416 square inches. Subtract 3.1416 from 12.5664 and the resultant area on the retraction stroke of the pneumatic cylinder would be equal to 9.4248 square inches. If the air pressure remains the same, at 100PSI, then the force would be equal to 942.48 pounds of force.

<< Pneumatic Ball Valves' Function And Structure Feature How to Fix a Pneumatic Chair >>
pneumatic | solenoid valve
Home  About us  Honor&culture   Products  New products  News center   |  Download Contact us
Copyright 2009 © Ningbo Lida Pneumatic Complete Sets Co.,Ltd. All Rights Reserved